Hallo allemaal,


Yesterday I wrote Joe Foster a PM asking if he could tell me how he read
the data from disk. During writing this email I got this idea:
- use one turn of the floppy to find out in which order the sectors are
stored.
- then start reading/writing the sectors with an interleave.

This interleave depends on how long it takes it to perform three
actions. The timing is measured in sectors:
1) reading a sector - 1 sector.
2) en/decoding the sector - I have no idea.
3) reading/writing the data from/to the harddisk + initialising the HD
for the next setor - IMHO < 1 sector.

If 2) would take one sector ie. interleave = 3, then it would take 4
revolutions to read a track or 24 seconds to store a disk. Much faster
then the 3 minutes I need now.

I know there is a routine the 1541 uses to find the right header to
cover 1). 3) isn't a problem either. Regarding 2) I have two qestions:
- I know the routines exists and should be able to find out how to use
it but if somebody happens to have some experience on this matter, info
is welcome.
- I have no idea how much time it takes to en/decode a sector. Anyone?

Many thanks in advance! 


--
    ___
   / __|__
  / /  |_/     Groetjes, Ruud Baltissen
  \ \__|_\
   \___|       http://Ruud.C64.org







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