On Fri 25 May 2012 at 04:43:33 +0000, William Levak wrote: > This would result in a string of zeroes, but only one high bit. > This is what I observed. In the instance where the bit gave all > high outputs, this represents a string of zeroes of zero length. > This would mean that the changed odd number came where the high bit > shifted out of the register, resulting in the shift register > shifting out a one every time. I've seen a different pattern by now, I think. Still with basically the same program as before; I wrote 6 times 9 (%1001), then once 1, then many times 9 again. The pattern for bit 3 (period 8) was 0 0 0 0 0 0 0 1 1 1 1 1 1 0 1 0 0 0 0 0 0 1 0 1 1 1 1 1 1 0 1 0 0 0 0 0 0 1 0 etc This is 2 changes in the period of 8. Of course I've caused 2 changes with this; perhaps I should simplify the program. -Olaf. -- ___ Olaf 'Rhialto' Seibert -- There's no point being grown-up if you \X/ rhialto/at/xs4all.nl -- can't be childish sometimes. -The 4th Doctor Message was sent through the cbm-hackers mailing listReceived on 2012-05-25 09:00:05
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