On 2/17/2012 12:38 AM, Jim Brain wrote: > I can understand that if the 2n3904 was used to drive the TIP29, but > the TIP29 was biased on with a 1.5K resistor. The 2n3904 merely drove > the base to ground (.6V or so), thus removing current from the base. > Obviously, it would need to sink the 7.5mA through the resistor > (11.4/1500), but where was the resit of the current required? I got my schematics mixed up. The VIC/64 were biased with a resistor, but the PET drive T was biased by the 4401, and the 4401 was biased by the 1.5K resistor. Your original response makes more sense now. Jim Message was sent through the cbm-hackers mailing listReceived on 2012-02-17 07:00:26
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