Hallo Martijn,
> A-symmetrical stream #3: (101000):
>
> This one is totaly devastated. It hardly represents the signal it's supposed
> to be; there are -0v crossings where there shouldn't have been; the peak
At this moment I have so many questions that the mailserver certainly will bumo
this email. The problem isthat I have some knowledge of the hardware of a
CD-player and in this case it does not help. For one thing, there are DAC's
inside a CD-player and they need bits to make a sample. And this information
does not match with yours saying you put some bit patterns on a CD and they
don't come out exactly as expected. My first gues would be they would not come
out at all as expected. But they partly do so: confusion :(
If I got you right, in case of the 101000 bitstream you wanted to end up with a
wave-pattern which should look as similar as the bitpattern itself. But it
doesn't. My idea: what about recording some known "music"-bitpatterns and then
to look on the CD hoe the real bit pattern looks like?
Another idea: whabout only using the 22 and 11 KHz-signal? 22 KHz = 0 and 11
KHZ = 1.
so 1010 1100 1010 1100 1100 1100 1010 1010 means:
0 1 0 1 1 1 0 0
This still means 11 Kbit/sec or 1 KByte (including sart and two stopbits).
Groetjes, Ruud
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